What is expand ((2x-1)(x+1))/2 ?

The solution to expand ((2x-1)(x+1))/2 is x^2+x/2-1/2

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expand ((2x-1)(x+1))/2

expand

\frac{( 2 x - 1 ) ( x + 1 )}{2}

x^{2} + \frac{x}{2} - \frac{1}{2}

Solution steps

\frac{( 2 x - 1 ) ( x + 1 )}{2}

Expand

(2 x - 1) (x + 1) : 2 x^{2} + x - 1

= \frac{2 x ^{2} + x - 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + x - 1}{2} = \frac{2 x ^{2}}{2} + \frac{x}{2} - \frac{1}{2}

= \frac{2 x ^{2}}{2} + \frac{x}{2} - \frac{1}{2}

Divide the numbers:

\frac{2}{2} = 1

= x^{2} + \frac{x}{2} - \frac{1}{2}

2 sin (3 t) [u (t - 2)]

\frac{30 + s}{s ( s + 10 )}

e^{x} (1 - e^{- x})

\frac{\partial}{\partial x} ((z) (yz - ln (x + z)))

\frac{6 x ^{5} + 3 x ^{4} - 7 x ^{3} + 5 x ^{2} - 8}{x ^{2} \cdot ( 3 x ^{2} - 2 )}

What is expand ((2x-1)(x+1))/2 ?
The solution to expand ((2x-1)(x+1))/2 is x^2+x/2-1/2