What is expand (4x^2(30-2x))/9 ?

The solution to expand (4x^2(30-2x))/9 is -(8x^3)/9+(40x^2)/3

Popular >

expand (4x^2(30-2x))/9

expand

\frac{4 x ^{2} ( 30 - 2 x )}{9}

- \frac{8 x ^{3}}{9} + \frac{40 x ^{2}}{3}

Solution steps

\frac{4 x ^{2} ( 30 - 2 x )}{9}

Expand

4 x^{2} (30 - 2 x) : 120 x^{2} - 8 x^{3}

= \frac{120 x ^{2} - 8 x ^{3}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{120 x ^{2} - 8 x ^{3}}{9} = \frac{120 x ^{2}}{9} - \frac{8 x ^{3}}{9}

= \frac{120 x ^{2}}{9} - \frac{8 x ^{3}}{9}

Cancel

\frac{120 x ^{2}}{9} : \frac{40 x ^{2}}{3}

= \frac{40 x ^{2}}{3} - \frac{8 x ^{3}}{9}

Rewrite in standard form

= - \frac{8 x ^{3}}{9} + \frac{40 x ^{2}}{3}

\frac{2 x ^{2} + 2 x y - 2 y ^{2}}{( 2 x + y ) ^{2}}

\frac{( 2 x + 3 )}{( x - 5 ) ( x + 4 )}

z [(n - 1) a^{n - 1}]

(2 - x) e^{x} + 2

\frac{( 1 - x - y ) ^{3}}{3}

What is expand (4x^2(30-2x))/9 ?
The solution to expand (4x^2(30-2x))/9 is -(8x^3)/9+(40x^2)/3