What is expand-1/((x+1)(x-1)(x^2+1)) ?

The solution to expand-1/((x+1)(x-1)(x^2+1)) is -1/(x^4-1)

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expand-1/((x+1)(x-1)(x^2+1))

expand

- \frac{1}{( x + 1 ) ( x - 1 ) ( x ^{2} + 1 )}

- \frac{1}{x ^{4} - 1}

Solution steps

- \frac{1}{( x + 1 ) ( x - 1 ) ( x ^{2} + 1 )}

Expand

(x + 1) (x - 1) (x^{2} + 1) : x^{4} - 1

= - \frac{1}{x ^{4} - 1}

\frac{x \cdot ( x - 1 ) \cdot ( x - 2 )}{6}

(2 \cdot (- 3) y = - 1,) (k x + (k - 1) y - 2 (k + 2) = 0,)

\frac{5 x ^{2} - 26 x + 21}{( - x + 5 ) ( - x + 3 )}

(ln (x) - 1)^{2}

(x y - 4 x) d x - (x^{2} y + y) d y

What is expand-1/((x+1)(x-1)(x^2+1)) ?
The solution to expand-1/((x+1)(x-1)(x^2+1)) is -1/(x^4-1)