What is 2x^2+5x-3<= x^2+4x+3 ?

The solution to 2x^2+5x-3<= x^2+4x+3 is -3<= x<= 2

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2x^2+5x-3<= x^2+4x+3

2 x^{2} + 5 x - 3 \leq x^{2} + 4 x + 3

- 3 \leq x \leq 2

Solution steps

2 x^{2} + 5 x - 3 \leq x^{2} + 4 x + 3

Rewrite in standard form

x^{2} + x - 6 \leq 0

Factor

x^{2} + x - 6 : (x - 2) (x + 3)

(x - 2) (x + 3) \leq 0

Identify the intervals

- 3 \leq x \leq 2

3 \cdot 1 0^{- 6}

75 m^{2} - 12 m^{4}

- 16 x^{2} + 20 x + 84

(x - 2)^{2} + x^{2} = 1 0^{2}

60 t + 36 \geq 300

What is 2x^2+5x-3<= x^2+4x+3 ?
The solution to 2x^2+5x-3<= x^2+4x+3 is -3<= x<= 2