What is expand (3x^2+4x-7)/((x+1)(x-3)) ?

The solution to expand (3x^2+4x-7)/((x+1)(x-3)) is (3x^2+4x-7)/(x^2-2x-3)

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expand (3x^2+4x-7)/((x+1)(x-3))

expand

\frac{3 x ^{2} + 4 x - 7}{( x + 1 ) ( x - 3 )}

\frac{3 x ^{2} + 4 x - 7}{x ^{2} - 2 x - 3}

Solution steps

\frac{3 x ^{2} + 4 x - 7}{( x + 1 ) ( x - 3 )}

Expand

(x + 1) (x - 3) : x^{2} - 2 x - 3

= \frac{3 x ^{2} + 4 x - 7}{x ^{2} - 2 x - 3}

\frac{2 s + 5}{( s - 3 ) ^{2}}

\frac{2 ( x + 1 )}{x - 1}

2 x e^{x} + e^{x} (x^{2} - 8)

(x + 2) sin (y) d x + x cos (y) d y

\frac{5 x ( 2 x - 1 ) ^{4}}{3 y ^{7}}

What is expand (3x^2+4x-7)/((x+1)(x-3)) ?
The solution to expand (3x^2+4x-7)/((x+1)(x-3)) is (3x^2+4x-7)/(x^2-2x-3)