What is expand (f(c+h)-fc^')/h ?

The solution to expand (f(c+h)-fc^')/h is (cf)/h+f-(c^'f)/h

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expand (f(c+h)-fc^')/h

expand

\frac{f ( c + h ) - f c ^{^{'}}}{h}

\frac{c f}{h} + f - \frac{c ^{'} f}{h}

Solution steps

\frac{f ( c + h ) - f c ^{^{'}}}{h}

Expand

f (c + h) - f c^{^{'}} : c f + f h - f c^{^{'}}

= \frac{c f + f h - c ^{^{'}} f}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{c f + f h - f c ^{^{'}}}{h} = \frac{c f}{h} + \frac{f h}{h} - \frac{f c ^{^{'}}}{h}

= \frac{c f}{h} + \frac{f h}{h} - \frac{c ^{^{^{'}}} f}{h}

Cancel

\frac{f h}{h} : f

= \frac{c f}{h} + f - \frac{c ^{^{^{'}}} f}{h}

- 14 (- 2 e^{- x^{2}} x^{2} + e^{- x^{2}})

\frac{( x + 1 ) x ( x - 1 )}{6}

B D + B (C + E) + D^{^{'}} (D + F)

(\frac{a + b}{2}) (\frac{a - b}{2})

\frac{x ^{4} - 4 x ^{3} + 6 x ^{2} ( a + 2 ) \cdot ( b + 3 )}{x ^{2} + 2 x + 1}

What is expand (f(c+h)-fc^')/h ?
The solution to expand (f(c+h)-fc^')/h is (cf)/h+f-(c^'f)/h