What is expand-1/3 (e^{-3(-3+t)}-1) ?

The solution to expand-1/3 (e^{-3(-3+t)}-1) is -1/3 e^{9-3t}+1/3

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expand-1/3 (e^{-3(-3+t)}-1)

expand

- \frac{1}{3} (e^{- 3 (- 3 + t)} - 1)

- \frac{1}{3} e^{9 - 3 t} + \frac{1}{3}

Solution steps

- \frac{1}{3} (e^{- 3 (- 3 + t)} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = - \frac{1}{3}, b = e^{- 3 (- 3 + t)}, c = 1

= - \frac{1}{3} e^{- 3 (- 3 + t)} - (- \frac{1}{3}) \cdot 1

Apply minus-plus rules

- (- a) = a

= - \frac{1}{3} e^{- 3 (- 3 + t)} + 1 \cdot \frac{1}{3}

Simplify

- \frac{1}{3} e^{- 3 (- 3 + t)} + 1 \cdot \frac{1}{3} : - \frac{1}{3} e^{9 - 3 t} + \frac{1}{3}

= - \frac{1}{3} e^{9 - 3 t} + \frac{1}{3}

e^{(- 1 + 2 i) t}

2.7 (5.1 x + 4.9 = 3.2 x + 28.9)

- \frac{5 x - 1}{x ( x - 1 ) ^{2} ( 2 x + 3 )}

\frac{1}{( x + 1 ) ( - x + 1 )}

A (- 2, - 4) y B (5, 4)

What is expand-1/3 (e^{-3(-3+t)}-1) ?
The solution to expand-1/3 (e^{-3(-3+t)}-1) is -1/3 e^{9-3t}+1/3