What is expand (-4x^2+3x+6)/(2(2x+1)(3x-2)) ?

The solution to expand (-4x^2+3x+6)/(2(2x+1)(3x-2)) is (-4x^2+3x+6)/(12x^2-2x-4)

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expand (-4x^2+3x+6)/(2(2x+1)(3x-2))

expand

\frac{- 4 x ^{2} + 3 x + 6}{2 ( 2 x + 1 ) ( 3 x - 2 )}

\frac{- 4 x ^{2} + 3 x + 6}{12 x ^{2} - 2 x - 4}

Solution steps

\frac{- 4 x ^{2} + 3 x + 6}{2 ( 2 x + 1 ) ( 3 x - 2 )}

Expand

2 (2 x + 1) (3 x - 2) : 12 x^{2} - 2 x - 4

= \frac{- 4 x ^{2} + 3 x + 6}{12 x ^{2} - 2 x - 4}

(7, 1) y (7, - 5)

\frac{9 x ^{3} + 3 x ^{2} y - 5 x y ^{2} + y ^{3}}{( 3 x - y ) ( x + y )}

sin (3 3^{\circ} + 4 2^{\circ})

- \frac{( x + 1 ) ^{3} ( 3 ln ( x + 1 ) + 1 )}{9}

\frac{8 x - 19}{( x + 2 ) ( x - 5 )}

What is expand (-4x^2+3x+6)/(2(2x+1)(3x-2)) ?
The solution to expand (-4x^2+3x+6)/(2(2x+1)(3x-2)) is (-4x^2+3x+6)/(12x^2-2x-4)