What is expand (e^{-x}-e^x)^2 ?

The solution to expand (e^{-x}-e^x)^2 is e^{-2x}-2+e^{2x}

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expand (e^{-x}-e^x)^2

expand

(e^{- x} - e^{x})^{2}

e^{- 2 x} - 2 + e^{2 x}

Solution steps

(e^{- x} - e^{x})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = e^{- x}, b = e^{x}

= (e^{- x})^{2} - 2 e^{- x} e^{x} + (e^{x})^{2}

Simplify

(e^{- x})^{2} - 2 e^{- x} e^{x} + (e^{x})^{2} : e^{- 2 x} - 2 + e^{2 x}

= e^{- 2 x} - 2 + e^{2 x}

\frac{( k ^{14} + 4 k ^{7} + 3 )}{2 k ^{11} + 2 k ^{4}}

2 x e^{x^{2} - y^{2}} + 2 x (x^{2} + y^{2}) e^{x^{2} - y^{2}}

\frac{\partial}{\partial x} ((z) (z^{3} - z - x y))

\frac{s}{( s ^{2} + 1 ) ( s + 1 ) ^{2} ( s + 2 )}

\frac{d}{d x} \frac{( φ ( x ^{2} + 2 y ( φ , x ) ) + ψ ( φ , x , y ( φ , x ) ) ( x - 2 y ( φ , x ) ( φ , x ) ^{2} ) )}{x}

What is expand (e^{-x}-e^x)^2 ?
The solution to expand (e^{-x}-e^x)^2 is e^{-2x}-2+e^{2x}