What is expand (x+1)/((x-1)(x-3)) ?

The solution to expand (x+1)/((x-1)(x-3)) is (x+1)/(x^2-4x+3)

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expand (x+1)/((x-1)(x-3))

expand

\frac{x + 1}{( x - 1 ) ( x - 3 )}

\frac{x + 1}{x ^{2} - 4 x + 3}

Solution steps

\frac{x + 1}{( x - 1 ) ( x - 3 )}

Expand

(x - 1) (x - 3) : x^{2} - 4 x + 3

= \frac{x + 1}{x ^{2} - 4 x + 3}

\frac{d}{d x} ((7 t^{2} - 9 t) (5 t + 8)) - 1

\frac{1}{( s + 1 ) s ^{2}}

\frac{π}{12} (3 R h^{2} - h^{3})

\frac{2 ( x - 1 )}{x ^{3}}

(x^{3} - 2 x^{2} + \frac{π}{4}) (x^{2} - e) + x^{3} - 5 x + 7

What is expand (x+1)/((x-1)(x-3)) ?
The solution to expand (x+1)/((x-1)(x-3)) is (x+1)/(x^2-4x+3)