What is expand 8+(8-cos(4t))U(t-2pi) ?

The solution to expand 8+(8-cos(4t))U(t-2pi) is 8+8tU-16piU-tUcos(4t)+2piUcos(4t)

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expand 8+(8-cos(4t))U(t-2pi)

expand

8 + (8 - cos (4 t)) U (t - 2 π)

8 + 8 t U - 16 π U - t U cos (4 t) + 2 π U cos (4 t)

Solution steps

8 + (8 - cos (4 t)) U (t - 2 π)

= 8 + U (8 - cos (4 t)) (t - 2 π)

Expand

(8 - cos (4 t)) U (t - 2 π) : 8 t U - 16 π U - t U cos (4 t) + 2 π U cos (4 t)

= 8 + 8 t U - 16 π U - t U cos (4 t) + 2 π U cos (4 t)

\frac{lo g _{10} ( x )}{( 1 + lo g _{10} ( x ) ) ^{2}}

ux (u d x + x d u)

\frac{x + 3}{( x - 5 ) ( x ^{2} + 7 )}

(e^{s i n (θ)} - 2 cos (4 θ))^{2}

(e^{x} - e^{2 x})^{2}

What is expand 8+(8-cos(4t))U(t-2pi) ?
The solution to expand 8+(8-cos(4t))U(t-2pi) is 8+8tU-16piU-tUcos(4t)+2piUcos(4t)