What is expand ((y-1)^2)/2 ?

The solution to expand ((y-1)^2)/2 is (y^2)/2-y+1/2

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expand ((y-1)^2)/2

expand

\frac{( y - 1 ) ^{2}}{2}

\frac{y ^{2}}{2} - y + \frac{1}{2}

Solution steps

\frac{( y - 1 ) ^{2}}{2}

(y - 1)^{2} = y^{2} - 2 y + 1

= \frac{y ^{2} - 2 y + 1}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{y ^{2} - 2 y + 1}{2} = \frac{y ^{2}}{2} - \frac{2 y}{2} + \frac{1}{2}

= \frac{y ^{2}}{2} - \frac{2 y}{2} + \frac{1}{2}

Divide the numbers:

\frac{2}{2} = 1

= \frac{y ^{2}}{2} - y + \frac{1}{2}

\frac{4 ( 3 - 4 j )}{5 ( - 2 + 3 j )}

\frac{( x + 2 ) ( x - 3 )}{( x - 1 ) ( x + 6 )}

\frac{4 x ^{2} + 3 x + 1}{( x + 3 ) ( 3 x + 1 )}

\frac{x ^{2} + 2 x y - y ^{2}}{( x + y ) ^{2}}

- (\frac{( 4 ( 2 x - b ) )}{( b ^{2} )})

What is expand ((y-1)^2)/2 ?
The solution to expand ((y-1)^2)/2 is (y^2)/2-y+1/2