What is expand ((e^x+1)(e^x-1))/(e^x) ?

The solution to expand ((e^x+1)(e^x-1))/(e^x) is e^x-1/(e^x)

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expand ((e^x+1)(e^x-1))/(e^x)

expand

\frac{( e ^{x} + 1 ) ( e ^{x} - 1 )}{e ^{x}}

e^{x} - \frac{1}{e ^{x}}

Solution steps

\frac{( e ^{x} + 1 ) ( e ^{x} - 1 )}{e ^{x}}

Expand

(e^{x} + 1) (e^{x} - 1) : e^{2 x} - 1

= \frac{e ^{2 x} - 1}{e ^{x}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{2 x} - 1}{e ^{x}} = \frac{e ^{2 x}}{e ^{x}} - \frac{1}{e ^{x}}

= \frac{e ^{2 x}}{e ^{x}} - \frac{1}{e ^{x}}

Cancel

\frac{e ^{2 x}}{e ^{x}} : e^{x}

= e^{x} - \frac{1}{e ^{x}}

(x + y) d y + (1 - 2 y) d x

\frac{( n + 1 ) ^{2} ( n + 2 ) ^{2}}{4}

- 2 (5)^{2} + 400 (6) - 2000

e^{(50 (\frac{e ^{t} - 1}{t} - 1))}

e^{(- t - X)} \cdot u (t - X)

What is expand ((e^x+1)(e^x-1))/(e^x) ?
The solution to expand ((e^x+1)(e^x-1))/(e^x) is e^x-1/(e^x)