What is expand-(10x^2+6)/((x^2+x+1)(x^2-x+1)) ?

The solution to expand-(10x^2+6)/((x^2+x+1)(x^2-x+1)) is -(10x^2+6)/(x^4+x^2+1)

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expand-(10x^2+6)/((x^2+x+1)(x^2-x+1))

expand

- \frac{10 x ^{2} + 6}{( x ^{2} + x + 1 ) ( x ^{2} - x + 1 )}

- \frac{10 x ^{2} + 6}{x ^{4} + x ^{2} + 1}

Solution steps

- \frac{10 x ^{2} + 6}{( x ^{2} + x + 1 ) ( x ^{2} - x + 1 )}

Expand

(x^{2} + x + 1) (x^{2} - x + 1) : x^{4} + x^{2} + 1

= - \frac{10 x ^{2} + 6}{x ^{4} + x ^{2} + 1}

- \frac{3}{( s + 2 ) ( s + 1 )}

(x^{2} + 2)^{12}

(x - 1)^{2} (e^{x} - 1)

\frac{- 4 s - 11}{( s + 2 ) ^{2}}

ln (5) (5 - x^{4})

What is expand-(10x^2+6)/((x^2+x+1)(x^2-x+1)) ?
The solution to expand-(10x^2+6)/((x^2+x+1)(x^2-x+1)) is -(10x^2+6)/(x^4+x^2+1)