What is expand (3^{(x+1)(x+2)}+65)/(72) ?

The solution to expand (3^{(x+1)(x+2)}+65)/(72) is (3^{x^2+3x})/8+65/72

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expand (3^{(x+1)(x+2)}+65)/(72)

expand

\frac{3 ^{(x + 1) (x + 2)} + 65}{72}

\frac{3 ^{x^{2} + 3 x}}{8} + \frac{65}{72}

Solution steps

\frac{3 ^{(x + 1) (x + 2)} + 65}{72}

Expand

(x + 1) (x + 2) : x^{2} + 3 x + 2

= \frac{3 ^{x^{2} + 3 x + 2} + 65}{72}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 ^{x^{2} + 3 x + 2} + 65}{72} = \frac{3 ^{x^{2} + 3 x + 2}}{72} + \frac{65}{72}

= \frac{3 ^{x^{2} + 3 x + 2}}{72} + \frac{65}{72}

\frac{3 ^{x^{2} + 3 x + 2}}{72} = \frac{3 ^{x^{2} + 3 x}}{8}

= \frac{3 ^{x^{2} + 3 x}}{8} + \frac{65}{72}

\frac{2 ( n + 1 ) ( 2 n + 1 )}{3 n ^{2}}

\frac{1}{s ( s ^{2} + 4 s + 5 )}

\frac{π \cdot h ^{2} ( 3 r - h )}{3}

x^{2} (cos (2 x + 3 y) (2 + 3 y)) + 2 x sin (2 x + 3 y)

\frac{3 ( 9 x ^{2} + 1 )}{2}

What is expand (3^{(x+1)(x+2)}+65)/(72) ?
The solution to expand (3^{(x+1)(x+2)}+65)/(72) is (3^{x^2+3x})/8+65/72