What is expand (x-3)\circ (5x^2-3) ?

The solution to expand (x-3)\circ (5x^2-3) is 5\circ x^3-15\circ x^2-3\circ x+9\circ

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expand (x-3)\circ (5x^2-3)

expand

(x - 3) \circ (5 x^{2} - 3)

5 \circ x^{3} - 15 \circ x^{2} - 3 \circ x + 9 \circ

Solution steps

(x - 3) \circ (5 x^{2} - 3)

= \circ (x - 3) (5 x^{2} - 3)

Expand

(x - 3) (5 x^{2} - 3) : 5 x^{3} - 15 x^{2} - 3 x + 9

= \circ (5 x^{3} - 15 x^{2} - 3 x + 9)

Expand

\circ (5 x^{3} - 15 x^{2} - 3 x + 9) : 5 \circ x^{3} - 15 \circ x^{2} - 3 \circ x + 9 \circ

= 5 \circ x^{3} - 15 \circ x^{2} - 3 \circ x + 9 \circ

lo g_{10} (2) (b^{3} c)

3 (\frac{1}{3} (x - 4)) + 4

(3 + j)^{5}

\frac{x}{( x + 3 ) ( x + 2 )}

\frac{25 K ( T s + 1 )}{49 K + 25 T s + 125 T s ^{2} + 49 K T s}

What is expand (x-3)\circ (5x^2-3) ?
The solution to expand (x-3)\circ (5x^2-3) is 5\circ x^3-15\circ x^2-3\circ x+9\circ