What is expand (p(x))/((x-1)(x+1)(x-2)(x+2)) ?

The solution to expand (p(x))/((x-1)(x+1)(x-2)(x+2)) is (px)/(x^4-5x^2+4)

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expand (p(x))/((x-1)(x+1)(x-2)(x+2))

expand

\frac{p ( x )}{( x - 1 ) ( x + 1 ) ( x - 2 ) ( x + 2 )}

\frac{p x}{x ^{4} - 5 x ^{2} + 4}

Solution steps

\frac{p ( x )}{( x - 1 ) ( x + 1 ) ( x - 2 ) ( x + 2 )}

Remove parentheses:

(a) = a

= \frac{p x}{( x - 1 ) ( x + 1 ) ( x - 2 ) ( x + 2 )}

Expand

(x - 1) (x + 1) (x - 2) (x + 2) : x^{4} - 5 x^{2} + 4

= \frac{p x}{x ^{4} - 5 x ^{2} + 4}

\frac{4}{s ^{2} ( s + 2 )}

\frac{1}{p ( 1 - p )}

2 (2 e^{- x} x - e^{- x} x^{2})

\frac{- 2 e ^{- x^{2}} x ^{3} - 4 e ^{- x^{2}} x}{( x ^{2} + 1 ) ^{2}}

\frac{1}{s ( a ^{2} + s ^{2} )}

What is expand (p(x))/((x-1)(x+1)(x-2)(x+2)) ?
The solution to expand (p(x))/((x-1)(x+1)(x-2)(x+2)) is (px)/(x^4-5x^2+4)