What is expand 3(8pi-(64pi-48sqrt(3))/9) ?

The solution to expand 3(8pi-(64pi-48sqrt(3))/9) is 24pi-(64pi)/3+16sqrt(3)

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expand 3(8pi-(64pi-48sqrt(3))/9)

expand

3 (8 π - \frac{64 π - 48 3}{9})

24 π - \frac{64 π}{3} + 163

Solution steps

3 (8 π - \frac{64 π - 48 3}{9})

Apply the distributive law:

a (b - c) = ab - a c

a = 3, b = 8 π, c = \frac{64 π - 48 3}{9}

= 3 \cdot 8 π - 3 \cdot \frac{64 π - 48 3}{9}

Simplify

3 \cdot 8 π - 3 \cdot \frac{64 π - 48 3}{9} : 24 π - \frac{64 π}{3} + 163

= 24 π - \frac{64 π}{3} + 163

- \frac{K}{x ( x - K )}

1 - cos^{2} (x)

3 (2 + Δ x)^{2}

\frac{1}{3} (\frac{e ^{\frac{x}{3}} H ( x )}{3} + e^{\frac{x}{3}} u^{'} (x) x)

(x^{2} - y^{2}) (e^{- x^{2} - y^{2}})

What is expand 3(8pi-(64pi-48sqrt(3))/9) ?
The solution to expand 3(8pi-(64pi-48sqrt(3))/9) is 24pi-(64pi)/3+16sqrt(3)