What is expand (i400)/((32-21i)) ?

The solution to expand (i400)/((32-21i)) is -1680/293+i 2560/293

Popular >

expand (i400)/((32-21i))

expand

\frac{i 400}{( 32 - 21 i )}

- \frac{1680}{293} + i \frac{2560}{293}

Solution steps

\frac{i 400}{32 - 21 i}

Multiply by the conjugate

\frac{32 + 21 i}{32 + 21 i}

= \frac{i 400 ( 32 + 21 i )}{( 32 - 21 i ) ( 32 + 21 i )}

Simplify

i 400 (32 + 21 i) : - 8400 + 12800 i

(32 - 21 i) (32 + 21 i) = 1465

= \frac{- 8400 + 12800 i}{1465}

Factor

- 8400 + 12800 i : 400 (- 21 + 32 i)

= \frac{400 ( - 21 + 32 i )}{1465}

Cancel the common factor:

5

= \frac{80 ( - 21 + 32 i )}{293}

Rewrite

\frac{80 ( - 21 + 32 i )}{293}

in standard complex form:

- \frac{1680}{293} + \frac{2560}{293} i

= - \frac{1680}{293} + \frac{2560}{293} i

\frac{d}{d t} ((x) (x^{2} + 3 x - 6))

e^{t} (cos (3 t) + i sin (3 t)) (- 2 + i)

\frac{1}{( 2 + j ) ( 1 - 2 j )}

\frac{s - s \cdot e ^{- 2 π s}}{( s ^{2} + 4 ) ^{2}}

\frac{1}{4} (e^{2 t} \cdot 2 t - e^{2 t})

What is expand (i400)/((32-21i)) ?
The solution to expand (i400)/((32-21i)) is -1680/293+i 2560/293