What is expand (2y(2x^3-3yx^2))/((x-y)^2) ?

The solution to expand (2y(2x^3-3yx^2))/((x-y)^2) is (4yx^3-6y^2x^2)/(x^2-2yx+y^2)

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expand (2y(2x^3-3yx^2))/((x-y)^2)

expand

\frac{2 y ( 2 x ^{3} - 3 y x ^{2} )}{( x - y ) ^{2}}

\frac{4 y x ^{3} - 6 y ^{2} x ^{2}}{x ^{2} - 2 y x + y ^{2}}

Solution steps

\frac{2 y ( 2 x ^{3} - 3 y x ^{2} )}{( x - y ) ^{2}}

(x - y)^{2} = x^{2} - 2 y x + y^{2}

= \frac{2 y ( 2 x ^{3} - 3 y x ^{2} )}{x ^{2} - 2 y x + y ^{2}}

Expand

2 y (2 x^{3} - 3 y x^{2}) : 4 y x^{3} - 6 y^{2} x^{2}

= \frac{4 y x ^{3} - 6 y ^{2} x ^{2}}{x ^{2} - 2 y x + y ^{2}}

\frac{4 ab}{( a - b ) ( a + b )}

\frac{13}{( 2 x + 1 ) ^{2}}

\frac{x}{( x - a ) ^{2} ( x - b ) ^{2}}

\frac{\partial}{\partial x} ((f (x, y)) (x + 4 y))

\frac{( 4 x - 2 ) d x}{x ^{3} - x ^{2} - 2 x}

What is expand (2y(2x^3-3yx^2))/((x-y)^2) ?
The solution to expand (2y(2x^3-3yx^2))/((x-y)^2) is (4yx^3-6y^2x^2)/(x^2-2yx+y^2)