What is expand (q(l-x)^2)/l ?

The solution to expand (q(l-x)^2)/l is lq-2qx+(qx^2)/l

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expand (q(l-x)^2)/l

expand

\frac{q ( l - x ) ^{2}}{l}

lq - 2 q x + \frac{q x ^{2}}{l}

Solution steps

\frac{q ( l - x ) ^{2}}{l}

(l - x)^{2} = l^{2} - 2 l x + x^{2}

= \frac{q ( x ^{2} - 2 l x + l ^{2} )}{l}

Expand

q (l^{2} - 2 l x + x^{2}) : l^{2} q - 2 lq x + q x^{2}

= \frac{l ^{2} q - 2 lq x + q x ^{2}}{l}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{l ^{2} q - 2 lq x + q x ^{2}}{l} = \frac{l ^{2} q}{l} - \frac{2 lq x}{l} + \frac{q x ^{2}}{l}

= \frac{l ^{2} q}{l} - \frac{2 lq x}{l} + \frac{q x ^{2}}{l}

Cancel

\frac{l ^{2} q}{l} : lq

= lq - \frac{2 lq x}{l} + \frac{q x ^{2}}{l}

Cancel

\frac{2 lq x}{l} : 2 q x

= lq - 2 q x + \frac{q x ^{2}}{l}

\frac{45640}{( 1 + x ) ^{3}}

5.4 \cdot 1 0^{8} (1.3 \cdot 1 0^{- 11} - 5 \cdot 1 0^{- 12})

(- 3 - \frac{10 3}{9} i)^{\frac{1}{3}}

\frac{- 8 s + 88}{( s + 3 ) ( s + 1 )}

\frac{5 x ^{2} + 6 x + 12}{5 ( x ^{2} + 1 )}

What is expand (q(l-x)^2)/l ?
The solution to expand (q(l-x)^2)/l is lq-2qx+(qx^2)/l