What is expand ((4x+1)(5x-1))/(x^2-9) ?

The solution to expand ((4x+1)(5x-1))/(x^2-9) is (20x^2+x-1)/(x^2-9)

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expand ((4x+1)(5x-1))/(x^2-9)

expand

\frac{( 4 x + 1 ) ( 5 x - 1 )}{x ^{2} - 9}

\frac{20 x ^{2} + x - 1}{x ^{2} - 9}

Solution steps

\frac{( 4 x + 1 ) ( 5 x - 1 )}{x ^{2} - 9}

Expand

(4 x + 1) (5 x - 1) : 20 x^{2} + x - 1

= \frac{20 x ^{2} + x - 1}{x ^{2} - 9}

\frac{6 x ^{2} + 20 x + 3}{( 3 x + 5 ) ^{2}}

(\frac{x + 1}{2 x})^{9}

\frac{5 x ( 6480 - 5 x ^{2} )}{14}

2 + \frac{1}{2} cos (π (x + 1))

cos (2 t) - cos (2 (t - 2 π)) U (t - 2 π)

What is expand ((4x+1)(5x-1))/(x^2-9) ?
The solution to expand ((4x+1)(5x-1))/(x^2-9) is (20x^2+x-1)/(x^2-9)