What is (x-7)(4-x)(x+1)>= 0 ?

The solution to (x-7)(4-x)(x+1)>= 0 is x<=-1\lor 4<= x<= 7

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(x-7)(4-x)(x+1)>= 0

(x - 7) (4 - x) (x + 1) \geq 0

x \leq - 1 or 4 \leq x \leq 7

Interval Notation

(- \infty, - 1] \cup [4, 7]

Solution steps

(x - 7) (4 - x) (x + 1) \geq 0

Identify the intervals

x \leq - 1 or 4 \leq x \leq 7

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What is (x-7)(4-x)(x+1)>= 0 ?
The solution to (x-7)(4-x)(x+1)>= 0 is x<=-1\lor 4<= x<= 7