What is (d^2)/(dx^2)((y)(-6x^4+9)) ?

The answer to (d^2)/(dx^2)((y)(-6x^4+9)) is -6x^4(d^2y)/(dx^2)-48x^3(dy)/(dx)-72x^2y+9(d^2y)/(dx^2)

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(d^2)/(dx^2)((y)(-6x^4+9))

\frac{d ^{2}}{d x ^{2}} ((y) (- 6 x^{4} + 9))

- 6 x^{4} \frac{d ^{2} y}{d x ^{2}} - 48 x^{3} \frac{d y}{d x} - 72 x^{2} y + 9 \frac{d ^{2} y}{d x ^{2}}

Solution steps

\frac{d ^{2}}{d x ^{2}} ((y) (- 6 x^{4} + 9))

\frac{d}{d x} (y (- 6 x^{4} + 9)) = \frac{d y}{d x} (- 6 x^{4} + 9) - 24 x^{3} y

= \frac{d}{d x} (\frac{d y}{d x} (- 6 x^{4} + 9) - 24 x^{3} y)

\frac{d}{d x} (\frac{d y}{d x} (- 6 x^{4} + 9) - 24 x^{3} y) = - 6 x^{4} \frac{d ^{2} y}{d x ^{2}} - 48 x^{3} \frac{d y}{d x} - 72 x^{2} y + 9 \frac{d ^{2} y}{d x ^{2}}

= - 6 x^{4} \frac{d ^{2} y}{d x ^{2}} - 48 x^{3} \frac{d y}{d x} - 72 x^{2} y + 9 \frac{d ^{2} y}{d x ^{2}}

\frac{e ^{t}}{( s - 1 ) ^{2}}

\frac{( 2 t ^{3} - t ^{2} + 3 t - 1 )}{( t ^{2} + 1 ) ( t ^{2} + 2 )}

\frac{( 2 x - 3 ) ( 3 x - 1 )}{5 x ^{2} ( x - 5 )}

(8, - 2) (2 x - 5 y = - 12)

A (4, 7) y B (5, - 1)

What is (d^2)/(dx^2)((y)(-6x^4+9)) ?
The answer to (d^2)/(dx^2)((y)(-6x^4+9)) is -6x^4(d^2y)/(dx^2)-48x^3(dy)/(dx)-72x^2y+9(d^2y)/(dx^2)