What is expand ((D+3)t+(D+1)t^2)/(D^2+1) ?

The solution to expand ((D+3)t+(D+1)t^2)/(D^2+1) is (Dt+3t+Dt^2+t^2)/(D^2+1)

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expand ((D+3)t+(D+1)t^2)/(D^2+1)

expand

\frac{( D + 3 ) t + ( D + 1 ) t ^{2}}{D ^{2} + 1}

\frac{D t + 3 t + D t ^{2} + t ^{2}}{D ^{2} + 1}

Solution steps

\frac{( D + 3 ) t + ( D + 1 ) t ^{2}}{D ^{2} + 1}

Expand

(D + 3) t + (D + 1) t^{2} : D t + 3 t + D t^{2} + t^{2}

= \frac{D t + 3 t + D t ^{2} + t ^{2}}{D ^{2} + 1}

(t - 7) H (t - 5)

\frac{3 y ^{3} - x}{x ( x - y ^{3} )}

p (3, 4) p (- 4, - 3)

\frac{- s ^{3} + s - 2}{4 ( s ^{2} + 1 ) ^{2}}

\frac{2 ( u - 1 ) ^{3}}{u}

What is expand ((D+3)t+(D+1)t^2)/(D^2+1) ?
The solution to expand ((D+3)t+(D+1)t^2)/(D^2+1) is (Dt+3t+Dt^2+t^2)/(D^2+1)