What is expand-(Be^{Bx})/((1+e^{Bx))^2} ?

The solution to expand-(Be^{Bx})/((1+e^{Bx))^2} is -(Be^{Bx})/(1+2e^{Bx)+e^{2Bx}}

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expand-(Be^{Bx})/((1+e^{Bx))^2}

expand

- \frac{B e ^{B x}}{( 1 + e ^{B x} ) ^{2}}

- \frac{B e ^{B x}}{1 + 2 e ^{B x} + e ^{2 B x}}

Solution steps

- \frac{B e ^{B x}}{( 1 + e ^{B x} ) ^{2}}

(1 + e^{B x})^{2} = 1 + 2 e^{B x} + e^{2 B x}

= - \frac{B e ^{B x}}{2 e ^{B x} + e ^{2 B x} + 1}

(3 + 2 x - x^{2})^{5}

4 (1 - e^{- 0.13 t})

lo g_{10} (x^{7} y^{- 12})

\frac{5 x ^{2} - 8 x + 1}{( x + 1 ) ( x - 3 )}

\frac{x ( 3 x - 2 ) ( x - 2 )}{2 ( 3 x - 5 )}

What is expand-(Be^{Bx})/((1+e^{Bx))^2} ?
The solution to expand-(Be^{Bx})/((1+e^{Bx))^2} is -(Be^{Bx})/(1+2e^{Bx)+e^{2Bx}}