What is the d/(dy)((x)((x^2)/(c^2)-(y^9)/(d^2))) ?

The d/(dy)((x)((x^2)/(c^2)-(y^9)/(d^2))) is -(9xy^8)/(d^2)

What is the first d/(dy)((x)((x^2)/(c^2)-(y^9)/(d^2))) ?

The first d/(dy)((x)((x^2)/(c^2)-(y^9)/(d^2))) is -(9xy^8)/(d^2)

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\frac{d}{d y} ((x) (\frac{x ^{2}}{c ^{2}} - \frac{y ^{9}}{d ^{2}}))

- \frac{9 x y ^{8}}{d ^{2}}

Solution steps

\frac{d}{d y} ((x) (\frac{x ^{2}}{c ^{2}} - \frac{y ^{9}}{d ^{2}}))

Treat

c, d, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (\frac{x ^{2}}{c ^{2}} - \frac{y ^{9}}{d ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d}{d y} (\frac{x ^{2}}{c ^{2}}) - \frac{d}{d y} (\frac{y ^{9}}{d ^{2}}))

\frac{d}{d y} (\frac{x ^{2}}{c ^{2}}) = 0

\frac{d}{d y} (\frac{y ^{9}}{d ^{2}}) = \frac{9 y ^{8}}{d ^{2}}

= x (0 - \frac{9 y ^{8}}{d ^{2}})

Simplify

x (0 - \frac{9 y ^{8}}{d ^{2}}) : - \frac{9 x y ^{8}}{d ^{2}}

= - \frac{9 x y ^{8}}{d ^{2}}

\frac{3336.24}{0.89} - \frac{0.66 x}{0.89}

e^{3 (l n (x) + c)}

\frac{c - 1}{( c + 3 ) ( c - 4 )}

\frac{( 523 - 128 3 ) π}{6}

t^{3} - m p - 2 (p + m)

What is the d/(dy)((x)((x^2)/(c^2)-(y^9)/(d^2))) ?
The d/(dy)((x)((x^2)/(c^2)-(y^9)/(d^2))) is -(9xy^8)/(d^2)
What is the first d/(dy)((x)((x^2)/(c^2)-(y^9)/(d^2))) ?
The first d/(dy)((x)((x^2)/(c^2)-(y^9)/(d^2))) is -(9xy^8)/(d^2)