What is expand (6x^2-3x)/((x-2)(x+4)) ?

The solution to expand (6x^2-3x)/((x-2)(x+4)) is (6x^2-3x)/(x^2+2x-8)

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expand (6x^2-3x)/((x-2)(x+4))

expand

\frac{6 x ^{2} - 3 x}{( x - 2 ) ( x + 4 )}

\frac{6 x ^{2} - 3 x}{x ^{2} + 2 x - 8}

Solution steps

\frac{6 x ^{2} - 3 x}{( x - 2 ) ( x + 4 )}

Expand

(x - 2) (x + 4) : x^{2} + 2 x - 8

= \frac{6 x ^{2} - 3 x}{x ^{2} + 2 x - 8}

3 (e^{2 x} + x)^{2} (e^{2 x} \cdot 2 + 1)

(x - e^{y})^{2}

\frac{39 ( e ^{7} - 1 )}{7}

e^{(- 1 - π x) t} cos (π x) + e^{- t}

\frac{x ^{4} + 2 x + 1}{( x - 1 ) ( x ^{2} + 1 )}

What is expand (6x^2-3x)/((x-2)(x+4)) ?
The solution to expand (6x^2-3x)/((x-2)(x+4)) is (6x^2-3x)/(x^2+2x-8)