What is expand (9(x-3))/((x-2)(x-1)) ?

The solution to expand (9(x-3))/((x-2)(x-1)) is (9x-27)/(x^2-3x+2)

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expand (9(x-3))/((x-2)(x-1))

expand

\frac{9 ( x - 3 )}{( x - 2 ) ( x - 1 )}

\frac{9 x - 27}{x ^{2} - 3 x + 2}

Solution steps

\frac{9 ( x - 3 )}{( x - 2 ) ( x - 1 )}

Expand

(x - 2) (x - 1) : x^{2} - 3 x + 2

= \frac{9 ( x - 3 )}{x ^{2} - 3 x + 2}

Expand

9 (x - 3) : 9 x - 27

= \frac{9 x - 27}{x ^{2} - 3 x + 2}

\frac{( 4 e ^{x} - 2 ) e ^{x}}{( 2 e ^{x} + 1 ) ( e ^{x} + 2 )}

(x - 1)^{2} y^{''} (x) + (x - 1) y^{'} (x) - 4 y

(x + 2)^{2}

\frac{2 ( s ^{2} - 5 )}{( s ^{2} + 1 ) ( s ^{2} + 25 )}

\frac{t ^{3} e ^{2 t}}{( s - 2 ) ^{2}}

What is expand (9(x-3))/((x-2)(x-1)) ?
The solution to expand (9(x-3))/((x-2)(x-1)) is (9x-27)/(x^2-3x+2)