What is expand (x^2-2x+3)/((x-3)(x^2-9)) ?

The solution to expand (x^2-2x+3)/((x-3)(x^2-9)) is (x^2-2x+3)/(x^3-9x-3x^2+27)

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expand (x^2-2x+3)/((x-3)(x^2-9))

expand

\frac{x ^{2} - 2 x + 3}{( x - 3 ) ( x ^{2} - 9 )}

\frac{x ^{2} - 2 x + 3}{x ^{3} - 9 x - 3 x ^{2} + 27}

Solution steps

\frac{x ^{2} - 2 x + 3}{( x - 3 ) ( x ^{2} - 9 )}

Expand

(x - 3) (x^{2} - 9) : x^{3} - 9 x - 3 x^{2} + 27

= \frac{x ^{2} - 2 x + 3}{x ^{3} - 9 x - 3 x ^{2} + 27}

\frac{\partial}{\partial y} ((6 - \frac{y}{x}) \cdot y) - 2 y

2 ln (8)

e^{x} (2 x - x^{2})

, (2 t + 1) u_{1} (t)

- \frac{3}{s ( s ^{2} + 2 s + 17 )}

What is expand (x^2-2x+3)/((x-3)(x^2-9)) ?
The solution to expand (x^2-2x+3)/((x-3)(x^2-9)) is (x^2-2x+3)/(x^3-9x-3x^2+27)