What is expand (-x^2-3)/((x^2-3)^2) ?

The solution to expand (-x^2-3)/((x^2-3)^2) is (-x^2-3)/(x^4-6x^2+9)

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expand (-x^2-3)/((x^2-3)^2)

expand

\frac{- x ^{2} - 3}{( x ^{2} - 3 ) ^{2}}

\frac{- x ^{2} - 3}{x ^{4} - 6 x ^{2} + 9}

Solution steps

\frac{- x ^{2} - 3}{( x ^{2} - 3 ) ^{2}}

(x^{2} - 3)^{2} = x^{4} - 6 x^{2} + 9

= \frac{- x ^{2} - 3}{x ^{4} - 6 x ^{2} + 9}

\frac{π}{2} (x - 3)

\frac{x ^{3} - 5 x}{( 1 - x ) ^{3}}

\frac{( s ^{2} - 4 )}{s ( s ^{2} + 4 ) ^{2}}

(y - z^{2}) d y

\frac{( x ^{2} - 3 x + 7 ) d x}{( x ^{3} + x )}

What is expand (-x^2-3)/((x^2-3)^2) ?
The solution to expand (-x^2-3)/((x^2-3)^2) is (-x^2-3)/(x^4-6x^2+9)