What is expand-3/((s^2-2s+1)(s^2+4)) ?

The solution to expand-3/((s^2-2s+1)(s^2+4)) is -3/(s^4+5s^2-2s^3-8s+4)

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expand-3/((s^2-2s+1)(s^2+4))

expand

- \frac{3}{( s ^{2} - 2 s + 1 ) ( s ^{2} + 4 )}

- \frac{3}{s ^{4} + 5 s ^{2} - 2 s ^{3} - 8 s + 4}

Solution steps

- \frac{3}{( s ^{2} - 2 s + 1 ) ( s ^{2} + 4 )}

Expand

(s^{2} - 2 s + 1) (s^{2} + 4) : s^{4} + 5 s^{2} - 2 s^{3} - 8 s + 4

= - \frac{3}{s ^{4} - 2 s ^{3} + 5 s ^{2} - 8 s + 4}

(3 x^{3} - 2 x y + 3)^{4} x

, x (x + 1) (x - 4)

\frac{3 x}{( x + 1 ) ( x + 2 )}

\frac{d ^{2}}{d x ^{2}} ((y) (2 x^{2} + cos (x)))

\frac{8 ( - 3 x ^{2} + 2 )}{( x ^{2} + 2 ) ^{3}}

What is expand-3/((s^2-2s+1)(s^2+4)) ?
The solution to expand-3/((s^2-2s+1)(s^2+4)) is -3/(s^4+5s^2-2s^3-8s+4)