What is expand (e^x-e^{-x})*(e^x+e^{-x}) ?

The solution to expand (e^x-e^{-x})*(e^x+e^{-x}) is e^{2x}-e^{-2x}

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expand (e^x-e^{-x})*(e^x+e^{-x})

expand

(e^{x} - e^{- x}) \cdot (e^{x} + e^{- x})

e^{2 x} - e^{- 2 x}

Solution steps

(e^{x} - e^{- x}) (e^{x} + e^{- x})

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{x}, b = e^{- x}

= (e^{x})^{2} - (e^{- x})^{2}

Simplify

(e^{x})^{2} - (e^{- x})^{2} : e^{2 x} - e^{- 2 x}

= e^{2 x} - e^{- 2 x}

\frac{15 ( e - 1 )}{2 e}

\frac{\partial}{\partial t} ((z) (x^{2} + y^{5}))

\frac{\frac{1 + s ^{2}}{s ^{2}}}{s ^{2} + 3}

\frac{( x ^{3} + 7 x + 10 ) ( x + 5 )}{( x + 2 ) ( x ^{2} + 8 x + 12 )}

\frac{\partial}{\partial y} ((x) (- 2 x^{2} + y^{2}))

What is expand (e^x-e^{-x})*(e^x+e^{-x}) ?
The solution to expand (e^x-e^{-x})*(e^x+e^{-x}) is e^{2x}-e^{-2x}