What is expand (-9x^2+144x-576)/2+5x^2-80x+320 ?

The solution to expand (-9x^2+144x-576)/2+5x^2-80x+320 is (x^2)/2-8x+32

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expand (-9x^2+144x-576)/2+5x^2-80x+320

expand

\frac{- 9 x ^{2} + 144 x - 576}{2} + 5 x^{2} - 80 x + 320

\frac{x ^{2}}{2} - 8 x + 32

Solution steps

\frac{- 9 x ^{2} + 144 x - 576}{2} + 5 x^{2} - 80 x + 320

Combine the fractions

\frac{- 9 x ^{2} + 144 x - 576}{2} + 5 x^{2} - 80 x : \frac{x ^{2} - 16 x - 576}{2}

= \frac{x ^{2} - 16 x - 576}{2} + 320

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 16 x - 576}{2} = \frac{x ^{2}}{2} - \frac{16 x}{2} - \frac{576}{2}

= \frac{x ^{2}}{2} - \frac{16 x}{2} - \frac{576}{2} + 320

Divide the numbers:

\frac{16}{2} = 8

= \frac{x ^{2}}{2} - 8 x - \frac{576}{2} + 320

Divide the numbers:

\frac{576}{2} = 288

= \frac{x ^{2}}{2} - 8 x - 288 + 320

Add/Subtract the numbers:

- 288 + 320 = 32

= \frac{x ^{2}}{2} - 8 x + 32

- \frac{3 ( 1 + 249 )}{20}

\frac{x}{( x - 1 ) ( x - 2 ) ( x - 3 )}

(x - c)^{2} + y^{2} + (x + c)^{2} + y^{2}

\frac{2 ( 3 + 6 )}{3}

x^{\frac{1}{x} - 2} \cdot (1 - ln (x))

What is expand (-9x^2+144x-576)/2+5x^2-80x+320 ?
The solution to expand (-9x^2+144x-576)/2+5x^2-80x+320 is (x^2)/2-8x+32