What is expand (x^3-8x^2-1)/((x+3)(x-2)(x^2+1)) ?

The solution to expand (x^3-8x^2-1)/((x+3)(x-2)(x^2+1)) is (x^3-8x^2-1)/(x^4-5x^2+x^3+x-6)

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expand (x^3-8x^2-1)/((x+3)(x-2)(x^2+1))

expand

\frac{x ^{3} - 8 x ^{2} - 1}{( x + 3 ) ( x - 2 ) ( x ^{2} + 1 )}

\frac{x ^{3} - 8 x ^{2} - 1}{x ^{4} - 5 x ^{2} + x ^{3} + x - 6}

Solution steps

\frac{x ^{3} - 8 x ^{2} - 1}{( x + 3 ) ( x - 2 ) ( x ^{2} + 1 )}

Expand

(x + 3) (x - 2) (x^{2} + 1) : x^{4} - 5 x^{2} + x^{3} + x - 6

= \frac{x ^{3} - 8 x ^{2} - 1}{x ^{4} - 5 x ^{2} + x ^{3} + x - 6}

(e^{- x} - x)^{2}

(1 + y^{2}) d x + (x^{2} y + y) d y

\frac{20}{( S + 1 ) ( S ^{2} + 4 S + 13 )}

\frac{x ^{3} + 1}{x ( x - 1 ) ^{3}}

\frac{1}{( x + c ) ( x )}

What is expand (x^3-8x^2-1)/((x+3)(x-2)(x^2+1)) ?
The solution to expand (x^3-8x^2-1)/((x+3)(x-2)(x^2+1)) is (x^3-8x^2-1)/(x^4-5x^2+x^3+x-6)