What is expand ((3n)(3n+1))/((3n-1)(3n+2)) ?

The solution to expand ((3n)(3n+1))/((3n-1)(3n+2)) is (9n^2+3n)/(9n^2+3n-2)

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expand ((3n)(3n+1))/((3n-1)(3n+2))

expand

\frac{( 3 n ) ( 3 n + 1 )}{( 3 n - 1 ) ( 3 n + 2 )}

\frac{9 n ^{2} + 3 n}{9 n ^{2} + 3 n - 2}

Solution steps

\frac{( 3 n ) ( 3 n + 1 )}{( 3 n - 1 ) ( 3 n + 2 )}

Remove parentheses:

(a) = a

= \frac{3 n ( 3 n + 1 )}{( 3 n - 1 ) ( 3 n + 2 )}

Expand

(3 n - 1) (3 n + 2) : 9 n^{2} + 3 n - 2

= \frac{3 n ( 3 n + 1 )}{9 n ^{2} + 3 n - 2}

Expand

3 n (3 n + 1) : 9 n^{2} + 3 n

= \frac{9 n ^{2} + 3 n}{9 n ^{2} + 3 n - 2}

(y + x (x^{2} + y^{2})^{2}) d x + (y (x^{2} + y^{2})^{2} - x)

\frac{s}{( s - 1 ) ( s + 2 )}

\frac{1}{( x - 3 ) ^{5}}

\frac{2 s ^{3} - 3 s ^{2} + 10 s - 12}{( s ^{2} + 1 ) ( s - 2 ) ^{2}}

\frac{1}{( 1 + 4 x ) ^{4}}

What is expand ((3n)(3n+1))/((3n-1)(3n+2)) ?
The solution to expand ((3n)(3n+1))/((3n-1)(3n+2)) is (9n^2+3n)/(9n^2+3n-2)