What is expand 1/((1-bz)(1-az)) ?

The solution to expand 1/((1-bz)(1-az)) is 1/(1-az-bz+baz^2)

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expand 1/((1-bz)(1-az))

expand

\frac{1}{( 1 - b z ) ( 1 - a z )}

\frac{1}{1 - a z - b z + ba z ^{2}}

Solution steps

\frac{1}{( 1 - b z ) ( 1 - a z )}

Expand

(1 - b z) (1 - a z) : 1 - a z - b z + ba z^{2}

= \frac{1}{1 - a z - b z + ba z ^{2}}

e^{x} (- x e^{- x} - e^{- x})

\frac{200 x ^{2} - 1600 x + 2400}{( x ^{2} - 8 x + 20 ) ^{2}}

\frac{2}{( 2 s + 1 ) ( s + 1 )}

(\frac{n ( n + 1 ) ( 2 n + 1 )}{6}) (\frac{2}{n})^{3}

\frac{2 ( - 2 e ^{- x} cos ( 2 x ) - e ^{- x} sin ( 2 x ) )}{5}

What is expand 1/((1-bz)(1-az)) ?
The solution to expand 1/((1-bz)(1-az)) is 1/(1-az-bz+baz^2)