What is expand (2x-1)/((x+2)(3x^2-2x)) ?

The solution to expand (2x-1)/((x+2)(3x^2-2x)) is (2x-1)/(3x^3+4x^2-4x)

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expand (2x-1)/((x+2)(3x^2-2x))

expand

\frac{2 x - 1}{( x + 2 ) ( 3 x ^{2} - 2 x )}

\frac{2 x - 1}{3 x ^{3} + 4 x ^{2} - 4 x}

Solution steps

\frac{2 x - 1}{( x + 2 ) ( 3 x ^{2} - 2 x )}

Expand

(x + 2) (3 x^{2} - 2 x) : 3 x^{3} + 4 x^{2} - 4 x

= \frac{2 x - 1}{3 x ^{3} + 4 x ^{2} - 4 x}

\frac{2 x ^{4} - x ^{3} + 3 x ^{2} - A x + B}{( x + 1 ) ^{2}}

\frac{d}{d t} ((x) (- a x + b))

\frac{e ^{(5 - s) 9}}{5 - s}

c - d {β [π + α (E - N) - X] + r}

What is expand (2x-1)/((x+2)(3x^2-2x)) ?
The solution to expand (2x-1)/((x+2)(3x^2-2x)) is (2x-1)/(3x^3+4x^2-4x)