What are the solutions to the equation 7x^2-2x=0 ?

The solutions to the equation 7x^2-2x=0 are x= 2/7 ,x=0

Find the zeros of 7x^2-2x=0

The zeros of 7x^2-2x=0 are x= 2/7 ,x=0

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7 x^{2} - 2 x = 0

x = \frac{2}{7}, x = 0

Decimal Notation

x = 0.28571 \dots, x = 0

Solution steps

7 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 7}

x = \frac{- ( - 2 ) + 2}{2 \cdot 7} : \frac{2}{7}

x = \frac{- ( - 2 ) - 2}{2 \cdot 7} : 0

The solutions to the quadratic equation are:

x = \frac{2}{7}, x = 0

\frac{e ^{- 5} \cdot 5 ^{3}}{3 !}

x - 3 > 5

lo g_{3} (4 x)

\frac{3}{10} - \frac{1}{5}

2 x + 8 = 10

What are the solutions to the equation 7x^2-2x=0 ?
The solutions to the equation 7x^2-2x=0 are x= 2/7 ,x=0
Find the zeros of 7x^2-2x=0
The zeros of 7x^2-2x=0 are x= 2/7 ,x=0