What is expand 1/((x-1)^2(x-3)) ?

The solution to expand 1/((x-1)^2(x-3)) is 1/(x^3-5x^2+7x-3)

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expand 1/((x-1)^2(x-3))

expand

\frac{1}{( x - 1 ) ^{2} ( x - 3 )}

\frac{1}{x ^{3} - 5 x ^{2} + 7 x - 3}

Solution steps

\frac{1}{( x - 1 ) ^{2} ( x - 3 )}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{1}{( x ^{2} - 2 x + 1 ) ( x - 3 )}

Expand

(x^{2} - 2 x + 1) (x - 3) : x^{3} - 5 x^{2} + 7 x - 3

= \frac{1}{x ^{3} - 5 x ^{2} + 7 x - 3}

- x^{2} (cot (3 y) + x^{3} y sin (3 y) d y)

(x + 4) \cdot ln (\frac{x + 12}{x + 4})

x d (y + y_{2}) d y_{2} + (1 - 2 y_{2}) d y

(2 + 5 = 6,) V (5 - 3 = 4)

\frac{2 x + 1}{x ^{2} ( 2 x - 1 )}

What is expand 1/((x-1)^2(x-3)) ?
The solution to expand 1/((x-1)^2(x-3)) is 1/(x^3-5x^2+7x-3)