What is expand Dx[(x-1)(4-2x)] ?

The solution to expand Dx[(x-1)(4-2x)] is -2Dx^3+6Dx^2-4Dx

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expand Dx[(x-1)(4-2x)]

expand

D x [(x - 1) (4 - 2 x)]

- 2 D x^{3} + 6 D x^{2} - 4 D x

Solution steps

D x ((x - 1) (4 - 2 x))

Remove parentheses:

(a) = a

= D x (x - 1) (4 - 2 x)

Expand

(x - 1) (4 - 2 x) : - 2 x^{2} + 6 x - 4

= D x (- 2 x^{2} + 6 x - 4)

Expand

D x (- 2 x^{2} + 6 x - 4) : - 2 D x^{3} + 6 D x^{2} - 4 D x

= - 2 D x^{3} + 6 D x^{2} - 4 D x

(x + 1) \cdot e^{x}

\frac{5 ( q ^{6} - 3 q ^{4} + 3 q ^{2} )}{3}

(x^{3} - 2) e^{- 3 x - 5}

\frac{e ^{- s}}{s ^{2} ( s + 2 )}

(1 - 3 i)^{10}

What is expand Dx[(x-1)(4-2x)] ?
The solution to expand Dx[(x-1)(4-2x)] is -2Dx^3+6Dx^2-4Dx