What is (\partial)/(\partial t)((x)(xy(x^2+y^2))) ?

The answer to (\partial)/(\partial t)((x)(xy(x^2+y^2))) is 0

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(\partial)/(\partial t)((x)(xy(x^2+y^2)))

\frac{\partial}{\partial t} ((x) (x y (x^{2} + y^{2})))

0

Solution steps

\frac{\partial}{\partial t} ((x) (x y (x^{2} + y^{2})))

Simplify

(x) (x y (x^{2} + y^{2})) : x^{2} y (x^{2} + y^{2})

= \frac{\partial}{\partial t} (x^{2} y (x^{2} + y^{2}))

Treat

x, y

as constants

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{1125}{s ( s + 5 ) + 1125}

1.66 z (z - e^{- T}) (z - e^{- 0.6 T})

(- 2, - 3) y (4, 2)

(x^{2} + (y - c)^{2}) d x

\frac{d}{d x} ((5 x - 5) 32) - x^{34}

What is (\partial)/(\partial t)((x)(xy(x^2+y^2))) ?
The answer to (\partial)/(\partial t)((x)(xy(x^2+y^2))) is 0