What is expand (2s^2-9s-35)/((s+1)(s-2)(s+3)) ?

The solution to expand (2s^2-9s-35)/((s+1)(s-2)(s+3)) is (2s^2-9s-35)/(s^3+2s^2-5s-6)

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expand (2s^2-9s-35)/((s+1)(s-2)(s+3))

expand

\frac{2 s ^{2} - 9 s - 35}{( s + 1 ) ( s - 2 ) ( s + 3 )}

\frac{2 s ^{2} - 9 s - 35}{s ^{3} + 2 s ^{2} - 5 s - 6}

Solution steps

\frac{2 s ^{2} - 9 s - 35}{( s + 1 ) ( s - 2 ) ( s + 3 )}

Expand

(s + 1) (s - 2) (s + 3) : s^{3} + 2 s^{2} - 5 s - 6

= \frac{2 s ^{2} - 9 s - 35}{s ^{3} + 2 s ^{2} - 5 s - 6}

\frac{x + 1}{( x - 1 ) ^{3}}

\frac{( t + 2 ) ^{4}}{2}

0.5 (2 x + 20) (5, 2) + 2 x (15 - 2 x)

\frac{( n + 1 ) ^{2}}{2 n + 1}

\frac{5 x}{( 3 x - 2 ) ^{2}}

What is expand (2s^2-9s-35)/((s+1)(s-2)(s+3)) ?
The solution to expand (2s^2-9s-35)/((s+1)(s-2)(s+3)) is (2s^2-9s-35)/(s^3+2s^2-5s-6)