What is expand ((x^3+2)^3)/2 ?

The solution to expand ((x^3+2)^3)/2 is (x^9)/2+3x^6+6x^3+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x^3+2)^3)/2

expand

\frac{( x ^{3} + 2 ) ^{3}}{2}

\frac{x ^{9}}{2} + 3 x^{6} + 6 x^{3} + 4

Solution steps

\frac{( x ^{3} + 2 ) ^{3}}{2}

(x^{3} + 2)^{3} = x^{9} + 6 x^{6} + 12 x^{3} + 8

= \frac{x ^{9} + 6 x ^{6} + 12 x ^{3} + 8}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{9} + 6 x ^{6} + 12 x ^{3} + 8}{2} = \frac{x ^{9}}{2} + \frac{6 x ^{6}}{2} + \frac{12 x ^{3}}{2} + \frac{8}{2}

= \frac{x ^{9}}{2} + \frac{6 x ^{6}}{2} + \frac{12 x ^{3}}{2} + \frac{8}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{x ^{9}}{2} + 3 x^{6} + \frac{12 x ^{3}}{2} + \frac{8}{2}

Divide the numbers:

\frac{12}{2} = 6

= \frac{x ^{9}}{2} + 3 x^{6} + 6 x^{3} + \frac{8}{2}

Divide the numbers:

\frac{8}{2} = 4

= \frac{x ^{9}}{2} + 3 x^{6} + 6 x^{3} + 4

\frac{13}{( 20 - x ) ^{2}}

2 π (2 r^{2} sin (a) - r^{2} cos (a) 2 a)

\frac{7 ( 2 + 3 sin ( 2 x ) ) ( 2 x + 3 sin ^{2} ( x ) ) ^{\frac{4}{3}}}{3}

\frac{4 x ^{2}}{( 2 + x ) ( 3 + x )}

What is expand ((x^3+2)^3)/2 ?
The solution to expand ((x^3+2)^3)/2 is (x^9)/2+3x^6+6x^3+4