What is expand derivative of (x-1tan(x))+xsin(x) ?

The solution to expand derivative of (x-1tan(x))+xsin(x) is derivative of xtan(x-tan(x))+xsin(x)

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expand derivative of (x-1tan(x))+xsin(x)

expand

\frac{d}{d x} ((x - 1) tan (x)) + x sin (x)

\frac{d}{d x} (x tan (x) - tan (x)) + x sin (x)

Solution steps

\frac{d}{d x} ((x - 1) tan (x)) + x sin (x)

Expand

(x - 1) tan (x) : x tan (x) - tan (x)

= \frac{d}{d x} (x tan (x) - tan (x)) + x sin (x)

\frac{s ( 1 - e ^{- 2 π s} )}{s ^{2} + 4}

\frac{sin ( z )}{z ^{2} \cdot ( z - 4 )}

e^{x} (e^{y} + 2 y e^{- x})

\frac{d}{d x} ((z) (x + 2 y + z - 2 x y z))

What is expand derivative of (x-1tan(x))+xsin(x) ?
The solution to expand derivative of (x-1tan(x))+xsin(x) is derivative of xtan(x-tan(x))+xsin(x)