What is expand (2x^4+ax^3+(1-a)x^2+ax+(3-a))/(x-1) ?

The solution to expand (2x^4+ax^3+(1-a)x^2+ax+(3-a))/(x-1) is (2x^4+ax^3+x^2-ax^2+ax+3-a)/(x-1)

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expand (2x^4+ax^3+(1-a)x^2+ax+(3-a))/(x-1)

expand

\frac{2 x ^{4} + a x ^{3} + ( 1 - a ) x ^{2} + a x + ( 3 - a )}{x - 1}

\frac{2 x ^{4} + a x ^{3} + x ^{2} - a x ^{2} + a x + 3 - a}{x - 1}

Solution steps

\frac{2 x ^{4} + a x ^{3} + ( 1 - a ) x ^{2} + a x + ( 3 - a )}{x - 1}

Remove parentheses:

(a) = a

= \frac{2 x ^{4} + a x ^{3} + ( 1 - a ) x ^{2} + a x + 3 - a}{x - 1}

Expand

2 x^{4} + a x^{3} + (1 - a) x^{2} + a x + 3 - a : 2 x^{4} + a x^{3} + x^{2} - a x^{2} + a x + 3 - a

= \frac{2 x ^{4} + a x ^{3} + x ^{2} - a x ^{2} + a x + 3 - a}{x - 1}

(\frac{10 + x}{x - 2}) (\frac{3}{10 - x})

\frac{x}{( x + 1 ) ^{2}} + \frac{2}{x ^{1}}

2^{39} - 2^{11}

\frac{( - 2 a ^{2} - 1 ) ( 4 a ^{4} - 2 a ^{2} + 1 )}{8}

\frac{i}{( a + bi ) ^{2}}

What is expand (2x^4+ax^3+(1-a)x^2+ax+(3-a))/(x-1) ?
The solution to expand (2x^4+ax^3+(1-a)x^2+ax+(3-a))/(x-1) is (2x^4+ax^3+x^2-ax^2+ax+3-a)/(x-1)