What are the solutions to the equation 13x^2-5x+1=0 ?

The solutions to the equation 13x^2-5x+1=0 are x= 5/26+i(3sqrt(3))/(26),x= 5/26-i(3sqrt(3))/(26)

Find the zeros of 13x^2-5x+1=0

The zeros of 13x^2-5x+1=0 are x= 5/26+i(3sqrt(3))/(26),x= 5/26-i(3sqrt(3))/(26)

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13 x^{2} - 5 x + 1 = 0

x = \frac{5}{26} + i \frac{3 3}{26}, x = \frac{5}{26} - i \frac{3 3}{26}

Solution steps

13 x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 13 \cdot 1}{2 \cdot 13}

Simplify

(- 5)^{2} - 4 \cdot 13 \cdot 1 : 33 i

x_{1, 2} = \frac{- ( - 5 ) \pm 3 3 i}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3 3 i}{2 \cdot 13}, x_{2} = \frac{- ( - 5 ) - 3 3 i}{2 \cdot 13}

x = \frac{- ( - 5 ) + 3 3 i}{2 \cdot 13} : \frac{5}{26} + i \frac{3 3}{26}

x = \frac{- ( - 5 ) - 3 3 i}{2 \cdot 13} : \frac{5}{26} - i \frac{3 3}{26}

The solutions to the quadratic equation are:

x = \frac{5}{26} + i \frac{3 3}{26}, x = \frac{5}{26} - i \frac{3 3}{26}

16 x^{2} + 80 x = 0

\frac{1}{25} \cdot \frac{5}{2}

\frac{8 x}{2 y - 3 x} - \frac{3 y}{3 x - 2 y}

(9 x - 4)^{2} = 16

0. 2^{2} + 0. 2^{2}

What are the solutions to the equation 13x^2-5x+1=0 ?
The solutions to the equation 13x^2-5x+1=0 are x= 5/26+i(3sqrt(3))/(26),x= 5/26-i(3sqrt(3))/(26)
Find the zeros of 13x^2-5x+1=0
The zeros of 13x^2-5x+1=0 are x= 5/26+i(3sqrt(3))/(26),x= 5/26-i(3sqrt(3))/(26)