What is expand-4/((s+1)(s+2)(s-1)) ?

The solution to expand-4/((s+1)(s+2)(s-1)) is -4/(s^3+2s^2-s-2)

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expand-4/((s+1)(s+2)(s-1))

expand

- \frac{4}{( s + 1 ) ( s + 2 ) ( s - 1 )}

- \frac{4}{s ^{3} + 2 s ^{2} - s - 2}

Solution steps

- \frac{4}{( s + 1 ) ( s + 2 ) ( s - 1 )}

Expand

(s + 1) (s + 2) (s - 1) : s^{3} + 2 s^{2} - s - 2

= - \frac{4}{s ^{3} + 2 s ^{2} - s - 2}

\frac{- 4 x ^{3} - 10 x ^{2} - 4 x + 2}{( x ^{2} + 1 ) ^{4}}

\frac{( 8 + x ) ( x ^{2} + 1 )}{2}

(x - 2 + 2)^{2} (x - 2 - 2)^{2}

\frac{d}{d y} ((x (y)) (y^{2} + 1))

\frac{1}{( x - 1 ) ( x - 4 )}

What is expand-4/((s+1)(s+2)(s-1)) ?
The solution to expand-4/((s+1)(s+2)(s-1)) is -4/(s^3+2s^2-s-2)