What is expand (x-3)e^{|x+1|} ?

The solution to expand (x-3)e^{|x+1|} is e^{|x+1|}x-3e^{|x+1|}

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expand (x-3)e^{|x+1|}

expand

(x - 3) e^{∣ x + 1 ∣}

e^{∣ x + 1 ∣} x - 3 e^{∣ x + 1 ∣}

Solution steps

(x - 3) e^{∣ x + 1 ∣}

= e^{∣ x + 1 ∣} (x - 3)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{∣ x + 1 ∣}, b = x, c = 3

= e^{∣ x + 1 ∣} x - e^{∣ x + 1 ∣} \cdot 3

= e^{∣ x + 1 ∣} x - 3 e^{∣ x + 1 ∣}

(t - 2) cos (3 t) e^{2 t}

(\frac{a + x}{1 - a x})^{2}

\frac{z ( 1.1353 z + 0.5941 )}{( z - 1 ) ( z ^{2} + 0.7294 )}

\frac{3}{( x ^{2} + 4 ) \cdot ( x ^{2} + 9 )}

π (2 x + 1)^{2} (6 x)

What is expand (x-3)e^{|x+1|} ?
The solution to expand (x-3)e^{|x+1|} is e^{|x+1|}x-3e^{|x+1|}