What is expand (x^2+1)sec(h)(ln(x)) ?

The solution to expand (x^2+1)sec(h)(ln(x)) is x^2ln(x)sec(h)+ln(x)sec(h)

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expand (x^2+1)sec(h)(ln(x))

expand

(x^{2} + 1) sec (h) (ln (x))

x^{2} ln (x) sec (h) + ln (x) sec (h)

Solution steps

(x^{2} + 1) sec (h) (ln (x))

= (ln (x)) sec (h) (x^{2} + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = sec (h) (ln (x)), b = x^{2}, c = 1

= sec (h) (ln (x)) x^{2} + sec (h) (ln (x)) \cdot 1

= x^{2} (ln (x)) sec (h) + 1 \cdot (ln (x)) sec (h)

Simplify

x^{2} (ln (x)) sec (h) + 1 \cdot (ln (x)) sec (h) : x^{2} ln (x) sec (h) + ln (x) sec (h)

= x^{2} ln (x) sec (h) + ln (x) sec (h)

5 - 3 5 + 6

\frac{d}{d x} ((x - 3) e^{x}) - (x + 1) e^{- x}

\frac{c ( b + 4 )}{( c + d )}

5 (2.5)^{3} - 3 (2.5)^{2} - 6 (2.5) - 16

\frac{( x - 1 ) \cdot ( x - 2 )}{( x + 3 ) \cdot ( x + 4 )}

What is expand (x^2+1)sec(h)(ln(x)) ?
The solution to expand (x^2+1)sec(h)(ln(x)) is x^2ln(x)sec(h)+ln(x)sec(h)